The value of 1 81^ n - 10 81^ n ^ 2 n c_ 1 + 10^ 2 81^ n ^ 2 n c_ 2 - 10^ 3 81^ n ^ 2 n…

Mathematics · JEE Main · NTA ExamsBinomial Theorem And Its Simple Applications

The value of \(\frac{1}{81^{n}}-\frac{10}{81^{n}} \cdot{ }^{2 n} c_{1}+\frac{10^{2}}{81^{n}} \cdot{ }^{2 n} c_{2}-\frac{10^{3}}{81^{n}} \cdot{ }^{2 n} c_{3}+\ldots+\frac{10^{2 n}}{81^{n}}\) is
  1. 2
  2. 0
  3. \(\frac{1}{2}\)
  4. 1

Answer

(B) 0

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