The coefficient of x 18 in the product (1+x)(1-x)^ 1 (1+x+x^ 2 )^ 3 is:
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
The coefficient of x18 in the product \((1+x)(1-x)^{1}\left(1+x+x^{2}\right)^{3}\) is:
- 126
- -84
- -126
- 84
Answer
(C) -126
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- In the expansion of (x^ 3 - 1 x^ 2 )^ 15 , the constant term is :
- If | x |<1 , then the coefficient of x ^ in expansion of (1+ x + x ^ 2 + x ^ 3 + )^ 2 is
- If the sum of the coefficients in the expansion of (a 2 x 2 – 6ax + 11) 10 , where a is constant, is 1024…
- Find the coefficient of x ^ in the series 1+(a+b x)+ (a+b x)^ 2 2! + (a+b x)^ 3 3! +
- The coefficient of x^ 5 in (1+2 x+3 x^ 2 + )^ - 3 2 is
- The number of terms in the expansions of (1+5 2 x)^ 9 +(1-5 2 x)^ 9 is
- 10 C 1 + 10 C 2 + 10 C 3 + .............+ 10 C 10 =
- If the coefficients of (r + 4)th term and (2r + 1)th term in the expansion of (1 + x) 18 are equal, then r =
More Binomial Theorem And Its Simple Applications questions · Browse all practice questions