In the expansion of (x^ 3 - 1 x^ 2 )^ 15 , the constant term is :
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
In the expansion of \(\left(x^{3}-\frac{1}{x^{2}}\right)^{15},\) the constant term is :
- \({ }^{15} \mathrm{C}_{\mathrm{g}}\)
- 0
- \({ }^{6} \partial_{51}-\)
- 1
Answer
(B) 0
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