If the sum of the coefficients in the expansion of (a 2 x 2 – 6ax + 11) 10 , where a is…
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
If the sum of the coefficients in the expansion of
(a2x2 – 6ax + 11)10, where a is constant, is 1024, then the value of a is :
(a2x2 – 6ax + 11)10, where a is constant, is 1024, then the value of a is :
- 5
- 1
- 2
- 3
Answer
(D) 3
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