C_ 1 1 + C_ 2 3 + C_ 4 5 + C_ 5 7 + is equal to
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
\(\frac{C_{1}}{1}+\frac{C_{2}}{3}+\frac{C_{4}}{5}+\frac{C_{5}}{7}+\ldots \text { is equal to }\)
- \(\frac{2^{n-1}}{n-1}\)
- \(\frac{2^{n+1}}{n+3}\)
- \(\frac{z^{n}}{n+1}\)
- \(\frac{2^{n-2}}{n}\)
Answer
(B) 2^ n+1 n+3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The coefficients of x^ p and x^ 4 in the expansion of (1+x)^ p+q are
- In the expansion of (2 x^ 2 - 1 x )^ 12 the term independent of x is :
- Given below are two statements. STATEMENT - 1: The total number of dissimilar terms in the expansion of ( x _…
- The sum of the coefficients of all odd degree terms in the expansion of (x+ x^ 3 -1 )^ 5 + (x- x^ 3 -1 )^ 5…
- The greatest integer in the expansion of (1+x)^ 2 n+2 is
- The value of n C 0 – n C 1 + n C 2 – .... + (–1) n n C n is
- Let 5_ n =1+q+q^ 2 + +q^ n and T_ n =1+ ( q+1 2 )+ ( q+1 2 )^ 2 + + ( q+1 2 )^ n where q is a real number and…
- Statement I : _ r =0 ^ n ( r +1) ^ n C _ r =( n +2) 2^ n -1 Statement II : _ r =0 ^ n ( r +1)^ n C _ r x ^ r…
More Binomial Theorem And Its Simple Applications questions · Browse all practice questions