If 0 ≤ x ≤ π, then the solution of the equation 16^ ^ 2 x + 16^ ^ 2 x = 10 is given by x…
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
If 0 ≤ x ≤ π, then the solution of the equation
\(16^{\sin ^{2} x}\) + \(16^{\cos ^{2} x}\) = 10 is given by x equal to
\(16^{\sin ^{2} x}\) + \(16^{\cos ^{2} x}\) = 10 is given by x equal to
- \(\frac{\pi}{6}, \frac{\pi}{3}\)
- \(\frac{\pi}{3}, \frac{\pi}{2}\)
- \(\frac{\pi}{6}, \frac{\pi}{2}\)
- none of these
Answer
(A) 6 , 3
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