If the expression x 2 – 11x + a and x 2 – 14x + 2a must have a common factor and a ≠ 0…
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
If the expression x2 – 11x + a and x2 – 14x + 2a must have a common factor and a ≠ 0, then, the common factor is
- (x – 3)
- (x – 6)
- (x – 8)
- none of these
Answer
(C) (x – 8)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If z lies on the circle centered at origin and if area of the triangle, whose vertices are z, ωz and z + ωz…
- If a , b , c , d are positive real numbers such that a + b + c + d = 2, then M = ( a + b ) ( c + d )…
- If θ ∈ (0, π), the principal value of the arg (z) and |z| of the complex number z= (1+ +i )^ 5 ( +i )^ 3 is
- If z 1 , z 2 , z 3 , z 4 are roots of the equation a 0 z 4 + a 1 z 3 + a 2 z 2 + a 3 z + a 4 = 0, where a 0 …
- The roots of the equation, (x 2 + 1) 2 = x(3x 2 + 4x + 3), are given by
- Let z 1 and z 2 be complex numbers such that Z _ 1 Z _ 2 and | z 1 | = | z 2 |. If z 1 has positive real part…
- For a R , | a | > 1, let Then the possible value(s) of a is/are
- If | array ccc 6 i & -3 i & 1 4 & 3 i & -1 20 & 3 & i array |=x+i y, then
More Complex Numbers and Quadratic Equations questions · Browse all practice questions