If z lies on the circle centered at origin and if area of the triangle, whose vertices…
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
If z lies on the circle centered at origin and if area of the triangle, whose vertices are z, ωz and z + ωz, (ω being an imaginary cube root of unity), is \(4 \sqrt{3}\)sq. units. Then radius of the circle is
- \(2\)
- \(8\)
- \(4\)
- \(16\)
Answer
(C) 4
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If a point z 1 is the reflection of a point z 2 through the line b z + b z = c b ≠ 0, in the Argand plane…
- If a < b < c < d, then for any positive λ, the quadratic equation (x – a) (x – c) + λ(x – b) (x – d) = 0 has
- If the quadratic equations ax 2 + 2cx + b = 0 and ax 2 + 2bx + c = 0 (b ≠ c) have a common root, then a + 4b…
- If ω ≠ 1 is a complex cube root of unity, then sum of the series S = 1 + 2ω + 3ω 2 + ... + 3nω 3n-1 (n ∈ N) is
- If p & q are roots of the equation x 2 – 2x + A = 0 and r & s be roots of the equation x 2 – 18 x + B = 0 if…
- If |z 2 – 1| = |z| 2 + 1, then z lies on
- If arg ( z _ 1 ) = arg (z 2 ), then
- The value of m for which one of the roots of x 2 – 3x + 2m = 0 is double of one of the roots of x 2 – x + m =…
More Complex Numbers and Quadratic Equations questions · Browse all practice questions