If ω ≠ 1 is a complex cube root of unity, then sum of the series S = 1 + 2ω + 3ω 2 + …
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
If ω ≠ 1 is a complex cube root of unity, then sum of the series S = 1 + 2ω + 3ω2 + ... + 3nω3n-1 (n ∈ N) is
- \(\frac{3 n}{\omega-1}\)
- \(n\left(\omega^{2}-1\right)\)
- 0
- 1
Answer
(A) 3 n -1, (B) n ( ^ 2 -1 )
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