If a < 0, then root of the equation x 2 – 2a |x – a| – 3a 2 = 0 is

Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations

1. \(\mathrm{a}(-1-\sqrt{6})\)
2. \(\mathrm{a}(1-\sqrt{2})\)
3. \(\mathrm{a}(-1+\sqrt{6})\)
4. \(\mathrm{a}(1+\sqrt{2})\)

Answer

(B) a (1- 2 ), (C) a (-1+ 6 )

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