If ‘x’ is real and satisfying the inequality, | x |< a x ( a R ), then
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
If ‘x’ is real and satisfying the inequality, \(|\mathrm{x}|<\frac{\mathrm{a}}{\mathrm{x}}(\mathrm{a} \in \mathrm{R}),\) then
- \(x \in(0, \sqrt{a}) \text { for } a>0\)
- \(\mathrm{x} \in(-\sqrt{\mathrm{a}}, 0) \text { for } \mathrm{a}<0\)
- \(x \in(-\sqrt{-a}, 0) \text { for } a<0\)
- \(x \in(-\sqrt{a}, \sqrt{a}) \text { for } a>0\)
Answer
(A) x (0, a ) for a>0, (C) x (- -a , 0) for a<0
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