_ 0 ^ / 2 ^ 5 ( x 2 ) x d x is equal to
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\int_{0}^{\pi / 2} \cos ^{5}\left(\frac{x}{2}\right) \cdot \sin x d x\) is equal to
- \(\frac{2}{7}\left(1-\frac{1}{8 \sqrt{2}}\right)\)
- \(\frac{-4}{7}\left(1-\frac{1}{8 \sqrt{2}}\right)\)
- \(\frac{4}{7}\left(1-\frac{1}{8 \sqrt{2}}\right)\)
- None of these
Answer
(C) 4 7 (1- 1 8 2 )
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Given below are two statements. Statement - 1: _ 0 ^ + y | x| d x=2 n+1- v where त E E and 0 v . Statement …
- If m is a non-zero number and x^ 5 m-1 +2 x^ 4 m-1 (x^ 2 m +x^ m +1 )^ 3 d x=f(x)+c then f(x) is
- The value of _ 0 ^ 2 x ^ 2 x ^ 2 x+ ^ 2 x d x is equal to :
- If A_ 1 = _ x ^ 1 1 1+t^ 2 d t and A_ 2 = _ 1 ^ 1 x 1 1+t^ 2 d t for x>0 , then
- _ 0 ^ 2 x x + x d x is equal to
- The integral _ 4 ^ 3 4 d x 1+ x is equal to
- e^ x (1-x)^ 2 (1+x^ 2 )^ 2 d x is equal to
- The value of I= _ 0 ^ 2 ( x+ x)^ 2 1+ 2 x d x is,
More Integral Calculus questions · Browse all practice questions