If m is a non-zero number and x^ 5 m-1 +2 x^ 4 m-1 (x^ 2 m +x^ m +1 )^ 3 d x=f(x)+c then…
Mathematics · JEE Main · NTA Exams — Integral Calculus
If m is a non-zero number and
\[\int \frac{x^{5 m-1}+2 x^{4 m-1}}{\left(x^{2 m}+x^{m}+1\right)^{3}} d x=f(x)+c\] then f(x) is
\[\int \frac{x^{5 m-1}+2 x^{4 m-1}}{\left(x^{2 m}+x^{m}+1\right)^{3}} d x=f(x)+c\] then f(x) is
- \[\frac{x^{5 m}}{2 m\left(x^{2 m}+x^{m}+1\right)^{2}}\]
- \[\frac{x^{4 m}}{2 m\left(x^{2 m}+x^{m}+1\right)^{2}}\]
- \[\frac{2 \mathrm{~m}\left(\mathrm{x}^{5 \mathrm{~m}}+\mathrm{x}^{4 \mathrm{~m}}\right)}{\left(\mathrm{x}^{2 \mathrm{~m}}+\mathrm{x}^{\mathrm{m}}+1\right)^{2}}\]
- \[\frac{\left(x^{5 \mathrm{~m}}-x^{4 \mathrm{~m}}\right)}{2 \mathrm{~m}\left(x^{2 \mathrm{~m}}+x^{\mathrm{m}}+1\right)^{2}}\]
Answer
(B) x^ 4 m 2 m (x^ 2 m +x^ m +1 )^ 2
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