The value of I= _ 0 ^ 2 ( x+ x)^ 2 1+ 2 x d x is,
Mathematics · JEE Main · NTA Exams — Integral Calculus
The value of \(I=\int_{0}^{\frac{\pi}{2}} \frac{(\sin x+\cos x)^{2}}{\sqrt{1+\sin 2 x}} d x\) is,
- 0
- 1
- 2
- 3
Answer
(B) 1
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