_ x 0^ + 1 x^ 3 _ 0 ^ x^ 2 t d t is equal to
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\lim _{x \rightarrow 0^{+}} \frac{1}{x^{3}} \int_{0}^{x^{2}} \sin \sqrt{t} d t\) is equal to
- \(\frac{1}{3}\)
- \(\frac{2}{3}\)
- \(-\frac{1}{3}\)
- \(-\frac{2}{3}\)
Answer
(B) 2 3
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