If A_ 1 = _ x ^ 1 1 1+t^ 2 d t and A_ 2 = _ 1 ^ 1 x 1 1+t^ 2 d t for x>0 , then
Mathematics · JEE Main · NTA Exams — Integral Calculus
\[\text { If } A_{1}=\int_{x}^{1} \frac{1}{1+t^{2}} d t \text { and } A_{2}=\int_{1}^{\frac{1}{x}} \frac{1}{1+t^{2}} d t \text { for } x>0 \text {, then }\]
- \(I_{1}=I_{2}\)
- \(I_{1}>I_{2}\)
- \(I_{2}>I_{1}\)
- None of these
Answer
(A) I_ 1 =I_ 2
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