If I _ n = _ 0 ^ / 4 ^ n d where n is a positive integer, then n (I_ n-1 +I_ n+1 ) is…
Mathematics · JEE Main · NTA Exams — Integral Calculus
If \(\mathrm{I}_{n}=\int_{0}^{\pi / 4} \tan ^{n} \theta d \theta\) where n is a positive integer, then \(n\left(I_{n-1}+I_{n+1}\right)\) is equal to
- \(1\)
- \(\frac{1}{n-1}\)
- none of these
Answer
(A) 1
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