If _ 0 ^ x f(t) d t=x^ 2 + _ x ^ 1 t^ 2 f(t) d t then f^ ( 1 2 ) is:
Mathematics · JEE Main · NTA Exams — Integral Calculus
If \(\int_{0}^{x} f(t) d t=x^{2}+\int_{x}^{1} t^{2} f(t) d t\) then \(f^{\prime}\left(\frac{1}{2}\right)\) is:
- \(\frac{16}{25}\)
- \(\frac{6}{25}\)
- \(\frac{24}{25}\)
- \(\frac{4}{5}\)
Answer
(B) 6 25
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