The integral _ 0 ^ 1 2 (1+2 x) 1+4 x^ 2 d x equals:
Mathematics · JEE Main · NTA Exams — Integral Calculus
The integral \[\int_{0}^{\frac{1}{2}} \frac{\ln (1+2 x)}{1+4 x^{2}} d x\] equals:
- \(\frac{\pi}{4} \ln 2\)
- \(\frac{\pi}{8} \ln 2\)
- \(\frac{\pi}{16} \ln 2\)
- \(\frac{\pi}{32} \ln 2\)
Answer
(C) 16 2
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