The area of the region bounded by the curve y=x-x^ 2 , x- axis between x=0 and x=1 is :
Mathematics · JEE Main · NTA Exams — Integral Calculus
The area of the region bounded by the curve
\(y=x-x^{2}, x-\) axis between \(x=0\) and \(x=1\) is :
\(y=x-x^{2}, x-\) axis between \(x=0\) and \(x=1\) is :
- \(\frac{1}{3}\)
- \(\frac{1}{2}\)
- \(\frac{5}{6}\)
Answer
(A)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The value(s) of _ 1 ^ 1 x^ 4 (1-x)^ 4 1+x^ 2 d x is (are),
- The area of the circle exterior to the parabola y^ 2 =6 x is :
- Given below are two statements. Statement - 1: If f(x)= _ 1 ^ x _ r t 1+t+t^ 2 d t then f(x)=f ( 1 x ) for…
- If . |_ n = _ 0 ^ / 4 ^ n x ^ 2 x d x, then . |_ 1 , . |_ 2 , . |_ 3 are in
- The area bounded by the curves y= x, y= x and y- axis in first quadrant is –
- Evaluate _ 1 ^ 1 x^ 2 d x .
- Evaluate _ 0 ^ 2 x- x 1+ x x d x
- ^ -1 x (1-x^ 2 )^ 3 / 2 d x is equal to
More Integral Calculus questions · Browse all practice questions