The area of the circle exterior to the parabola y^ 2 =6 x is :
Mathematics · JEE Main · NTA Exams — Integral Calculus
The area of the circle
exterior to the parabola \(y^{2}=6 x\) is :
exterior to the parabola \(y^{2}=6 x\) is :- \(\frac{4}{3}(4 \pi-\sqrt{3})\)
- \(\frac{4}{3}(4 \pi+\sqrt{3})\)
- \(\frac{4}{3}(8 \pi-\sqrt{3})\)
- \(\frac{4}{3}(8 \pi+\sqrt{3})\)
Answer
(C) 4 3 (8 - 3 )
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