If f(x)= [x^ 2 + ^ 2 x ] 1+x^ 2 ^ 2 x d x and f(0) = 0, then f(1) is
Mathematics · JEE Main · NTA Exams — Integral Calculus
If \(f(x)=\int \frac{\left[x^{2}+\sin ^{2} x\right]}{1+x^{2}} \sec ^{2} x d x\) and f(0) = 0, then f(1) is
- \(1-\frac{\pi}{4}\)
- \(\frac{\pi}{4}-1\)
- \(\tan 1-\frac{\pi}{4}\)
- None of these
Answer
(C) 1- 4
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