If f (x) is differentiable and _ 0 ^ t^ 2 x f(x) d x= 2 5 t^ 5 , then f ( 4 25 ) is equal…
Mathematics · JEE Main · NTA Exams — Integral Calculus
If f (x) is differentiable and \[\int_{0}^{t^{2}} x f(x) d x=\frac{2}{5} t^{5}, \text { then } f\left(\frac{4}{25}\right)\] is equal to
- \(\frac{2}{5}\)
- \(-\frac{2}{5}\)
- \(\frac{2}{\sqrt{5}}\)
- \(-\frac{2}{\sqrt{5}}\)
Answer
(B) - 2 5
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