_ 0 ^ x d x a^ 2 ^ 2 x+b^ 2 ^ 2 x is equal to
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\int_{0}^{\pi} \frac{x d x}{a^{2} \cos ^{2} x+b^{2} \sin ^{2} x}\) is equal to
- \(\frac{\pi}{2 a b}\)
- \(\frac{\pi}{a b}\)
- \(\frac{\pi^{2}}{2 a b}\)
- \(\frac{\pi^{2}}{a b}\)
Answer
(C) ^ 2 2 a b
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