Let f( x )=f( x )+f ( 1 x ) . where f(x)= _ 1 ^ x t 1+t d t . Then, F(e) equals
Mathematics · JEE Main · NTA Exams — Integral Calculus
Let \(f(\mathbf{x})=f(\mathbf{x})+f\left(\frac{1}{\mathbf{x}}\right) .\) \(\text { where } f(x)=\int_{1}^{x} \frac{\log t}{1+t} d t \text {. }\) Then, F(e) equals
- \(\frac{1}{2}\)
- 0
- 1
- 2
Answer
(A) 1 2
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