The area (in sq. units) of the smaller portion enclosed between the curves, x^ 2 +y^ 2 =4…
Mathematics · JEE Main · NTA Exams — Integral Calculus
The area (in sq. units) of the smaller portion enclosed between the curves, \(x^{2}+y^{2}=4 \text { and } y^{2}=3 x\), is:
- \(\frac{1}{\sqrt{3}}+\frac{4 \pi}{3}\)
- \(\frac{1}{\sqrt{3}}+\frac{2 \pi}{3}\)
- \(\frac{1}{2 \sqrt{3}}-\frac{\pi}{3}\)
- \(\frac{1}{2 \sqrt{3}}+\frac{2 \pi}{3}\)
Answer
(B) 1 3 + 2 3
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