( x-1) 1+( x)^ 2 ^ 2 dx is equal to
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\int\left\{\frac{(\log x-1)}{1+(\log x)^{2}}\right\}^{2}\)dx is equal to
- \(\frac{x}{x^{2}+1}+\mathrm{C}\)
- \(\frac{\log x}{(\log x)^{2}+1}+C\)
- \(\frac{x}{(\log x)^{2}+1}+\mathrm{C}\)
- \(\frac{x \mathrm{e}^{\mathrm{x}}}{1+x^{2}}+\mathrm{C}\)
Answer
(C) x ( x)^ 2 +1 + C
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