_ 0 ^ x f(t) d t=x+ _ x ^ 1 t f(t) d t , then the value of f(1) is
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\int_{0}^{x} f(t) d t=x+\int_{x}^{1} t f(t) d t\), then the value of \(\text { f(1) }\) is
- \(\frac{1}{2}\)
- 0
- 1
- \(-\frac{1}{2}\)
Answer
(B) 0
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