The value of the integral I= _ 0 ^ 1 x(1-x)^ n d x is:
Mathematics · JEE Main · NTA Exams — Integral Calculus
The value of the integral \(I=\int_{0}^{1} x(1-x)^{n} d x\) is:
- \(\frac{1}{n+2}\)
- \(\frac{1}{n+1}-\frac{1}{n+2}\)
- \(\frac{1}{n+1}+\frac{1}{n+2}\)
- \(\frac{1}{n+1}\)
Answer
(B) 1 n+1 - 1 n+2
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