A stationary body explodes into four identical fragments such that three of them fly off…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other, each with same KE, E0.The energy of explosion will be
- 6 E0
- \(\frac{4 \mathrm{E}_{0}}{3}\)
- 4 E0
- 8 E0
Answer
(A) 6 E 0
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