Block A and B shown in the figure are having equal masses m. The system is released from…
Physics · JEE Advanced · NTA Exams — Laws of Motion
Block A and B shown in the figure are having equal masses m. The system is released from rest with the spring unstretched. The string between A and ground is cut when there is maximum extension in the spring. The acceleration of centre of mass of the two blocks at this instant is :
- g
- \(\frac{g}{2}\)
- 2 g
- zero
Answer
(A) g
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Block A has a mass of 40 kg and block B has a mass of 15 kg, and F of 500 N is applied parallel to smooth…
- A projectile is moving at 60 m/s at its highest point, where it breaks into two equal parts due to an…
- A circular ring of mass 6 kg and radius a is placed such that its centre lies at the origin. Two particles of…
- Block A has a mass of 40 kg and block B has a mass of 15 kg, and F of 500 N is applied parallel to smooth…
- A circular plate of diameter d is kept in contact with a square plate of edge d as shown in figure. The…
- In the previous problem, when the string is taut the velocity of the centre of mass is :
- A 50 kg man is standing on a flat boat at rest in a river. He moves 5 m to north and halts. If the boat has a…
- A ball of mass m and radius ( R 10 ) is placed as shown, on a block B of mass 9 m which is placed on a smooth…
More Laws of Motion questions · Browse all practice questions