In the previous problem, when the string is taut the velocity of the centre of mass is :
Physics · JEE Advanced · NTA Exams — Laws of Motion
In the previous problem, when the string is taut the velocity of the centre of mass is :
- \(\frac{m_{0} \mathrm{v}_{0}}{\left(m_{0}+m\right)}\)
- \(\frac{2 m_{0} \mathrm{v}_{0}}{\left(m_{0}+m\right)}\)
- \(\frac{m_{0} \mathrm{v}_{0}}{\left(2 m_{0}+m\right)}\)
- \(\frac{\left(m_{0}+m\right) \mathrm{v}_{0}}{\left(2 m_{0}+m\right)}\)
Answer
(C) m_ 0 v _ 0 (2 m_ 0 +m )
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A piece of wire is bent in the shape of a parabola y = kx 2 ( y -axis vertical) with a bead of mass m on it…
- Two bodies with masses, m 1 and m 2 (m 1 > m 2 ) are joined by a string passing over a fixed pulley. The…
- A ball A of mass m is given an initial velocity to slide down and collide with ball B of mass (2m) so that…
- In a free space, a rifle of mass M shoots a bullet of mass m at a stationary block of mass M distance D away…
- Statement–1 : In one dimensional elastic collision between an incoming body A and body B which is at rest…
- A 50 kg man is standing on a flat boat at rest in a river. He moves 5 m to north and halts. If the boat has a…
- A ball A of mass 3 m is placed at a distance d from the wall on a smooth horizontal surface. Another ball B…
- Three blocks A, B and C of mass 3M, 2M and M, respectively, are suspended vertically with the help of springs…
More Laws of Motion questions · Browse all practice questions