A circular ring of mass 6 kg and radius a is placed such that its centre lies at the…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A circular ring of mass 6 kg and radius a is placed such that its centre lies at the origin. Two particles of masses 2 kg each are placed at the intersecting points of the circle with +ve x–axis and +ve y–axis. Then, the angle made by the position vector of centre of mass of entire system with x–axis is :
- 45°
- 60°
- \(\tan ^{-1}\left(\frac{4}{5}\right)\)
- 30°
Answer
(A) 45°
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