In the shown arrangement mass of A = 1 kg, mass of B = 2 kg. Coefficient of friction…
Physics · JEE Advanced · NTA Exams — Laws of Motion
In the shown arrangement mass of A = 1 kg, mass of B = 2 kg. Coefficient of friction between A and B = 0.2 . There is no friction between B and ground. The frictional force exerted by A on B equals:
- 2 N
- 3 N
- 4 N
- 5 N
Answer
(A) 2 N
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