The equation of the curve satisfying the differential equation d^ 2 y d x^ 2 (x^ 2 +1 )=2…

Mathematics · JEE Advanced · NTA ExamsDifferential Equations

The equation of the curve satisfying the differential equation \(\frac{d^{2} y}{d x^{2}}\left(x^{2}+1\right)=2 x \frac{d y}{d x}\) passing through the point (0, 1) and having slope of tangent at x = 0 as 3 is
  1. y = x2 + 3x + 2
  2. y2 = x2 + 3x + 1
  3. y = x3 + 3x + 1
  4. None of these

Answer

(C) y = x 3 + 3x + 1

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