The function y = f ( x ) is the solution of the differential equation d y d x + x y x^ 2…
Mathematics · JEE Advanced · NTA Exams — Differential Equations
The function y = f (x) is the solution of the differential equation \(\frac{d y}{d x}+\frac{x y}{x^{2}-1}=\frac{x^{4}+2 x}{\sqrt{1-x^{2}}}\) in (–1, 1) satisfying
f (0) = 0 . Then \[\int_{-\sqrt{3} / 2}^{\sqrt{3} / 2} f(x) d x\] is
f (0) = 0 . Then \[\int_{-\sqrt{3} / 2}^{\sqrt{3} / 2} f(x) d x\] is
Answer
(B)
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