If _ a ^ x t y(t) d t = x 2 + y (x) then y as a function of x is
Mathematics · JEE Advanced · NTA Exams — Differential Equations
If \(\int_{a}^{x} t y(t) d t\)= x2 + y (x) then y as a function of x is
- y = 2 – (2 + a2)\(e^{\frac{x^{2}-a^{2}}{2}}\)
- y = 1 – (2 + a2)\(e^{\frac{x^{2}-a^{2}}{2}}\)
- y = 2 – (1 + a2)\(e^{\frac{x^{2}-a^{2}}{2}}\)
- none
Answer
(A) y = 2 – (2 + a 2 ) e^ x^ 2 -a^ 2 2
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