A mass of 3 kg descending vertically downward supports a mass of 2 kg by means of a light…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A mass of 3 kg descending vertically downward supports a mass of 2 kg by means of a light string passing over a pulley. At the end of 5 s the string breaks. How much high from now the 2 kg mass will go? (g = 9.8 m/s2) [assume strings are very long and value of g remains constant]
- 4.9 m
- 9.8 m
- 16.9 m
- 2.45 m
Answer
(A) 4.9 m
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