A block slides down an inclined plane of slope of angle with a constant velocity. It is…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A block slides down an inclined plane of slope of angle \(\theta\) with a constant velocity. It is then projected up the plane with an initial velocity u. The distance up to which it will rise before coming to rest is:
- \(\frac{w^{2}}{4 g \sin \theta}\)
- \(\frac{u^{2}}{2 g}\)
- \(\frac{u^{2} \sin ^{2} \theta}{2 g}\)
- \(\frac{u \sin \theta}{2 g}\)
Answer
(A) w^ 2 4 g
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