A block of mass 5 kg moves along the x -direction subject to the force F = (−20 x + 10)…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A block of mass 5 kg moves along the x-direction subject to the force F = (−20x + 10) N, with the value of x in metre. At time t = 0 s, it is at rest at position x = 1 m. The position and momentum of the block at t = (p/4) s are
- −0.5 m, 5 kg m/s
- 0.5 m, 0 kg m/s
- 0.5 m, −5 kg m/s
- −1 m, 5 kg m/s
Answer
(C) 0.5 m, −5 kg m/s
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