If _ 10 (x^ 2 -3 x+6 )=1 then find the value of x.
Physics · NEET · NTA Exams — Basic Mathematics for Physics
If \(\log _{10}\left(x^{2}-3 x+6\right)=1\) then find the value of x.
- 3 or -1
- 4 or -1
- 4 or -2
- 3 or -2
Answer
(B) 4 or -1
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