If x=5 t^ 2 -4 t and y=9 t^ 3 +7 t^ 2 , then find the value of d y d x
Physics · NEET · NTA Exams — Basic Mathematics for Physics
If \(x=5 t^{2}-4 t\) and \(y=9 t^{3}+7 t^{2}\), then find the value of \(\frac{d y}{d x}\)
- \(\frac{t(27 t+14)}{10 t-4}\)
- \(\frac{t(27 t-14)}{10 t+4}\)
- \(\frac{t\left(27 t^{2}+14\right)}{10 t-4}\)
- None
Answer
(A) t(27 t+14) 10 t-4
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