Find the value of 42^ 48^ + 42^ 48^
Physics · NEET · NTA Exams — Basic Mathematics for Physics
Find the value of \(\sin 42^{\circ} \cos 48^{\circ}+\cos 42^{\circ} \sin 48^{\circ}\)
- 1
- 0
- 1/2
- \(\frac{1}{\sqrt{2}}\)
Answer
(A) 1
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