If 2=0.30103 and 3=0.47712 , then find the value of 51 26 + 91 119
Physics · NEET · NTA Exams — Basic Mathematics for Physics
If \(\log 2=0.30103 \text { and } \log 3=0.47712\), then find the value of \(\log \frac{51}{26}+\log \frac{91}{119}\)
- 0.19673
- 0.17609
- 0.16515
- 0.23415
Answer
(B) 0.17609
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