If 2=0.3010 and 3=0.4771 then find the value of log ( 27 32 625 )
Physics · NEET · NTA Exams — Basic Mathematics for Physics
If \(\log 2=0.3010 \text { and } \log 3=0.4771\) then find the value of log\(\left(\frac{27 \times 32}{625}\right)\)
- 1.5645
- 1.3824
- 0.1403
- 0.7985
Answer
(C) 0.1403
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