Let _ r =1 ^ n r ^ 4 =f( n ) then _ r =1 ^ n (2 r -1)^ 4 is equal to
Mathematics · JEE Advanced · NTA Exams — Progression and Series
Let \(\sum_{\mathrm{r}=1}^{\mathrm{n}} \mathrm{r}^{4}=f(\mathrm{n}) \text { then } \sum_{\mathrm{r}=1}^{\mathrm{n}}(2 \mathrm{r}-1)^{4}\)is equal to
- f (2n) – 16 f (n)
- f (2n) –7 f (n)
- f (2n – 1) –8( f (n)
- none of these
Answer
(A) f (2n) – 16 f (n)
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