Sum of the first n terms of the series 1 2 + 3 4 + 7 8 + 15 16 + . is equal to
Mathematics · JEE Advanced · NTA Exams — Progression and Series
Sum of the first n terms of the series \(\frac{1}{2}+\frac{3}{4}+\frac{7}{8}+\frac{15}{16}+\ldots \ldots .\)is equal to
- 2n – n – 1
- 1 – 2–n
- n + 2–n –1
- 2n +1
Answer
(C) n + 2 – n –1
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