Statement 1 : The sum of the series 1 + (1 + 2 + 4) + (4 + 6 + 9) + (9 + 12 + 16) + ... +…
Mathematics · JEE Advanced · NTA Exams — Progression and Series
Statement 1 : The sum of the series 1 + (1 + 2 + 4) +
(4 + 6 + 9) + (9 + 12 + 16) + ... + (361 + 380 + 400) is 8000 .
Statement 2 :\(\sum_{k=1}^{n}\left(k^{3}-(k-1)^{3}\right)=n^{3}\)for any natural number n.
(4 + 6 + 9) + (9 + 12 + 16) + ... + (361 + 380 + 400) is 8000 .
Statement 2 :\(\sum_{k=1}^{n}\left(k^{3}-(k-1)^{3}\right)=n^{3}\)for any natural number n.
- Statement 1 is true, Statement 2 is true; Statement 2 is not a correct explanation for Statement 1 .
- Statement 1 is true, Statement 2 is false.
- Statement 1 is false, Statement 2 is true.
- Statement 1 is true, Statement 2 is true;
Statement 2 is a correct explanation for Statement 1.
Answer
(D) Statement 1 is true, Statement 2 is true; Statement 2 is a correct explanation for Statement 1.
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