Let PQ and RS be tangents at the extremities of the diameter PR of a circle of radius r …
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
Let PQ and RS be tangents at the extremities of the diameter PR of a circle of radius r. If PS and RQ intersect at a point X on the circumference of the circle, then 2r equals.
- \(\sqrt{\text { Q. } \mathbf{R}}\)
- \(\frac{P+B}{2}\)
- \(\frac{2 \mathbb{Q} \cdot R}{Q+R}\)
- \(\sqrt{\frac{\mathbf{P}^{2}+\mathbf{R}^{2}}{2}}\)
Answer
(A) Q. R
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