The equation of the bisector of the angle between two lines 3x – 4y + 12 = 0 and 12x – 5y…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
The equation of the bisector of the angle between two lines 3x – 4y + 12 = 0 and 12x – 5y + 7 = 0 which contains the points (–1, 4) is :
- 21x + 27y – 121 = 0
- 21x – 27y + 121 = 0
- 21x + 27y + 191 = 0
- \(\frac{-3 x+4 y-2}{5}=\frac{2 x-5 y+7}{3}\)
Answer
(A) 21x + 27y – 121 = 0
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